LeetCode 2125 solution
2125. Number of Laser Beams in a Bank
# Medium # Array # Matrix
Anti-theft security devices are activated inside a bank. You are given a 0-indexed binary string arraybank
representing the floor plan of the bank, which is anm x n
2D matrix.bank[i]
represents theith
row, consisting of'0'
s and'1'
s.'0'
means the cell is empty, while'1'
means the cell has a security device.
There is one laser beam between any two security devices if both conditions are met:
The two devices are located on two different rows:r1
andr2
, wherer1 < r2
.
For each rowi
wherer1 < i < r2
, there are no security devices in theith
row.
Laser beams are independent, i.e., one beam does not interfere nor join with another.
Return the total number of laser beams in the bank.
Example 1:
Input: bank = ["011001","000000","010100","001000"]
Output: 8
Explanation: Between each of the following device pairs, there is one beam. In total, there are 8 beams:
* bank[0][1] -- bank[2][1]
* bank[0][1] -- bank[2][3]
* bank[0][2] -- bank[2][1]
* bank[0][2] -- bank[2][3]
* bank[0][5] -- bank[2][1]
* bank[0][5] -- bank[2][3]
* bank[2][1] -- bank[3][2]
* bank[2][3] -- bank[3][2]
Note that there is no beam between any device on the 0th row with any on the 3rd row.
This is because the 2nd row contains security devices, which breaks the second condition.
Python
class Solution:
def numberOfBeams(self, bank: List[str]) -> int:
one_list = []
result = []
for b in bank:
one = sum(1 for _ in b if _ == "1")
if one == 0:
continue
else:
one_list.append(one)
if len(one_list) == 1:
return 0
for i in range(len(one_list) - 1):
prev, next = one_list[i], one_list[i + 1]
result.append(prev * next)
return sum(result)
So simple algorithm it is. All you need to do is..
- count "1" in for each array
- if it's zero, skip that part
- iterate the recorded count of 1 and multiply one by one and record the result int
that all.